能被1到n的整数整除的数
能被1到n的整数整除的数
#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
bool isPrime(int n) {
if (n < 2)
return false;
for (int i = 2; i <= (int) sqrt((double) n); i++) {
if (n % i == 0)
return false;
}
return true;
}
int main(void)
{
int n;
cin >> n;
vector<int> v;
long long result = 1;
for (int i = 0; i <= n; i++)
{
if (isPrime(i))
{
v.push_back(i);
}
}
for (auto &i : v) {
int p = i;
while (p * i <= n)
p *= i;
result *= p;
}
cout << result % 987654321 << endl;
return 0;
}
Written on April 9, 2018